WebJan 3, 2016 · It is really simple. If they want you to find the major arc, then they can specify it in a couple of ways: 1. They can say Major arc AC. 2. Or, they can say the minor arc is arc ABC and the major arc is just AC. If the B is absent in one, then we can assume that B is not … WebAnswer (1 of 3): ABC and ADE are similar triangles, since DE is parallel to BC. AD/DB = AE/EC or 1.5/3 = 1/EC, or EC = 3*1/1.5 = 2. So AC = AE+EC =1+2 = 3 cm. AC = 3 cm.

In the given figure, BA∥ ED and BC∥ EF . Show that ABC

WebJun 2, 2015 · All you have to do is name the triangles the way the angles are equal. Say angle A = angle E, angle B = angle D and and hence angle C = angle F. Then we write: triangle AB C is similar to triangle ED F. Now you have the corresponding sides. That is, AB/ED = BC/DF = AC/EF. WebC OL OR A DO S P R I N G S NEWSPAPER T' rn arr scares fear to speak for the n *n and ike UWC. ti«(y fire slaves tch> ’n > » t \ m the nght i »ik two fir three'."—J. R. Lowed W E A T H E R F O R E C A S T P I K E S P E A K R E G IO N — Scattered anew flu m e * , h igh e r m ountain* today, otherw ise fa ir through Sunday. palmerston cinema

In Fig. 6.13, BA ED and BC EF. Show that ∠ ABC - Cuemath

WebApr 22, 2024 · In Fig, arms BA and BC of ∠ABC are respectively parallel to arms ED and EF of ∠DEF. Prove that ∠ABC + ∠DEF = 180° WebLet us extend DE to intersect BC at G, and EF to intersect BA at H. Then, the figure becomes. Since, BA DE. ⇒ BA GE. We have two parallel lines BA and GE, and BG is a transversal intersecting BA and GE at points B and G respectively. ⇒ ∠ABC = ∠EGC .....(i) Also, BC EF, and GE is a transversal intersecting BC and EF at points G ... WebStudies_on_t-ronic_resourced3Q»d3Q»BOOKMOBIq9 ð ³ µ #Ñ ,f 3· ) BL Jž R„ X7 _Ž g2 o¿ x) €œ …D" _$•_&œv(¤-*¬Ÿ,³Œ.¸”0½"2ÃÅ4Ȩ6Ïû8Ö :Ýžä">ì @óßBûjD ‹F ÓH ¾J ÀL ¬N ˆP R ÂìT rhV ’dX ÎÌZ ìh\ ô¼^ ø(` ˆb £üd ð f ‰0h íDj þÈl þìn ÿ p > $ MOBIè äÉ5Œ ... エクスペリエンス 意味