Web4 mrt. 2016 · List latestNewsList = latestNewses.stream () .map (objects -> new LatestNewsDTO (objects)) .collect (Collectors.toList ()); Now the LatestNewsDTO (Object [] objects) constructor can hold the logic that parses the array and sets the members of your instance. Share Improve this answer Follow edited Mar 4, 2016 at 7:59 Web25 jan. 2024 · Java8 Transform list of object to list of one attribute of object (1 answer) Closed 4 years ago. List customers = findAllCustomer (); public class …
JAVA 8 filter list of object with any matching property
WebYou need to use flatMap() in order to flatten the elements of the child list into a single list, otherwise you'd get a list of streams. Note 1: you don't need to use sequential(), since using stream() on the list of contacts already returns a sequential stream. Note 2: if you want the final list to be sorted, then you should use sorted() on the ... Web16 apr. 2015 · You can get a stream from the List and put in in the TreeSet from which you provide a custom comparator that compares id uniquely.. Then if you really need a list you can put then back this collection into an ArrayList. import static java.util.Comparator.comparingInt; import static … how big is 17.5 cm to inches
Get values of a Generic List object in Java - Stack Overflow
Web16 mrt. 2024 · Set keys = new HashSet<> (); for (Person person : personOutputList) { keys.addAll (inputMap.entrySet ().stream ().filter (entry -> Objects.equals (entry.getValue (), person)) .map (Map.Entry::getKey).collect (Collectors.toSet ())); } java lambda java-8 java-stream Share Improve this question Follow edited Mar 16, 2024 at 21:54 Web1 okt. 2024 · List nums = List.of (1, 2, 2); Map counts = nums.stream ().collect (Collectors.groupingBy (Function.identity (), Collectors.counting ())); return counts.entrySet ().stream ().filter (val -> val.getValue ().equals (1L)).map (Entry::getKey).findFirst ().orElse (-1); I found this answer in this post. Share Improve this … Web6 apr. 2024 · java 8: String [] names = Arrays.asStream (people).map (Person::getName).asArray (String []::new); Share Improve this answer Follow answered Apr 6, 2024 at 16:28 ZhenyaM 676 1 5 15 Add a comment -1 You are seeking a functional feature in an initially imperative-only language Java. how big is 16x24 on a wall