Django get latest for each group
WebMay 19, 2024 · yes, you can go ahead and test it. and print and check the queryset returned. I have a similar use case (considering the same model in the question), instead I had to fetch the latest record for each seller on each date. So I did this :- latest_sale = Sales.objects.order_by ("Saler", "-Date").distinct ("Saler") – Abhijeet Anand Shah. WebJul 5, 2024 · I want to get the latest score record for each student. I have tried: Score .objects ( 'student' .annotate (latest_date= Max 'date' )) Copy. and: Score …
Django get latest for each group
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WebMay 31, 2024 · Last record of each id ?! each record has only one unique id. But if you mean you want the object with the greatest id I think there are 2 ways to get the last object: queryset = model.objects.filter (id__in= [1, 5, 7]).order_by ('id').last () Or you can do this: queryset = model.objects.filter (id__in= [1, 5, 7]).latest ('id') Share WebI can use a queryset to return the latest update time for each location: latest_updates = Locations.objects.values ('location').annotate (max_date=Max ('update_time')).order_by ('location') but this only returns the location and max update_time when I'm looking for the entire row - num_01, num_02, num_03.
WebDjango ORM - Get latest record for group; Filtering Django Query by the Record with the Maximum Column Value; Django Raw Query: Making Count query with group BY … WebAug 14, 2024 · You can use slice operator to limit the query to a number of records. For example, limit to 10 latest records: UserData.objects.filter (user_id__in=user_list, date_created__lte=start_date) [:10]. Django querysets are lazy so this won't query all records and then slice it - it will only query 10. – vinkomlacic Aug 16, 2024 at 9:39 Add a …
Web[Answered]-Django Query Get Last Record with a Group By-django score:-1 Instead .order_by ('-month') [:1] it's better to use .order_by ('month').last () or .order_by ('-month').first () (or earliest / latest for dates). Of course when grouping you can use order_by: WebJan 31, 2024 · 1 Answer. Sorted by: 2. You may try this: MyModel.objects.filter ( #prepare subquery which has max dates per month #and limit resultset only to those dates date__in = Subquery ( MyModel.objects.annotate ( truncated_to_month = TruncMonth ('date') #used to group by truncated to month date ).values ( 'truncated_to_month' ).annotate ( …
WebMar 29, 2024 · 1 Answer. for each in People.objects.all (): score = models.CharField (verbose_name=each.title, max_length=4) Firstly even if the loop works there would only be one score field in the end. Next a Django model is the reflection of a Database table. Ever heard of a table having an arbitrary number of columns (atleast a good normalized table)?
WebJan 24, 2024 · To signify this, in Django positional arguments to .distinct () can be passed only in Postgresql ). In Django we can do this with QuerySet like this: Portfolio.objects.order_by ().order_by ( 'code', # first, cause we want to group by this value '-created' # descending order, latest / max will be first ).distinct ('code') planning applications islington councilWebGROUP BY and Select MAX from each group in Django, 2 queries Raw gistfile1.txt ''' given a Model with: category = models.CharField (max_length=32, choices=CATEGORY_CHOICES) pubdate = models.DateTimeField (default=datetime.now) Fetch the item from each category with the latest pubdate. ''' planning applications lincolnshire councilWebMar 1, 2024 · We can select top n per group with help of Subquery. Firstly, let's get top n Purchases per customer top_n_purchases_per_customer = Purchases.objects.filter ( customer=OuterRef ('customer') ).order_by ('-field_of_interest') [:10] Next, we can select Purchases with matching ids from the top 10 per each customer. planning applications longridge prestonWebSep 10, 2024 · A simple way to do this in a single query is to annotate each photo with the latest date for the related person and then filter by the annotation. This should return all desired PersonPhoto in a queryset. from django.db.models import Max, F PersonPhoto.objects.annotate ( latest=Max ('person__personphoto__date_captured') … planning applications longfordWebAug 21, 2015 · 1. I have a little problem with getting latest foreign key value in my django app. Here are my two models: class Stock (models.Model): ... class Dividend (models.Model): date = models.DateField ('pay date') stock = models.ForeignKey (Stock, related_name="dividends") class Meta: ordering = ["date"] I would like to get latest … planning applications long buckbyplanning applications longburton dorsetWebOct 7, 2015 · Now, i want to get the problems count for latest test for each name. For example if my table data is. name date problems count foo 10.10.15 50 foo 10.09.15 30 bar 10.07.15 23 foo 10.03.15 54 bar 05.03.15 31 foo 10.01.15 97 Then i would like to get. planning applications long lea hall rowarth